Thomas Weine
Cadet
- Joined
- Nov 29, 2019
The system worked liked this.101 10 might be the weight of the gun? I recall Britain used to use a antediluvian system of hundredths weight and some such?
The first number(s) would be multiplied by 112 lbs.
The second number was multiplied by 28 lbs. (28 is one fourth of 128)
The third number was simply lbs.
Adding the three numbers togethers gives the total weight of the tube.
The US Navy marked the weight of at least some tubes in this manner until the 1830s, possibly later.
If the number are 10110, it would have to as follows:
10 - 1 - 10 would be 28 plus 10, total 1158 lbs.
(101 X 112 plus 28 plus 10 would be 12, 508 lbs., many times the actual weight of this tube.)
10, 110 lbs. is likewise far too heavy.
I would estimate that the actual weight of this tube to be 700 to 800 lbs. I said estimate, or maybe guesstimate.
Although an iron 12 pdr., the shorter barrel and thin nature of the barrel, I think that the weight would make it lighter than many iron 12pdrs.used in the Civil War.
I wish we knew the answers to all the questions about this piece.